有懂SQL语句的帮金光整个法子

聶十八

哦用了count(*)
( |4 D; G6 I7 q) u# N2 D( b* Y* S没用group by

haney

文盲飘过

ftw

这个很难清出来吧？

三叶草

试试我QQ群里发的，

金光

select author, count(*) from pre_forum_post_2 as b where b.fid='105' and b.tid='863265' and first=0 and mod(( select count(*) as dd from pre_forum_post_2 as a where a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) ,25)=0 group by author

$ G/ P3 ]' Y; O$ Y$ j3 j4 q! \select ( select count(*) as dd from pre_forum_post_2 as a where  a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) as xuhao, author  from pre_forum_post_2 as b where b.fid='105' and b.tid='863265' and first=0 and mod(( select count(*) as dd from pre_forum_post_2 as a where  a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) ,25)=0
这个是显示发帖的楼层数